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共1个回答
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1、n=4时,f(4)=2;
2、n=5时,f(5)=5;
3、假设,n=k时,有f(k)=0.5k(k-3)
f(k+1)=f(k)+k-2=0.5k(k-3)+k+1-2=0.5(k^2-3k+2k-2)=0.5[(k^2-1)-(k+1)]
=0.5(k+1)(k+1-3)